[bigboy81]

how i can convert this to y_ini

PHP код:

new password2 = num_hash(password);
if(dini_Int(string2,"Password") == password2) 


i try something like this..

PHP код:

INI_Int("Password", == password2); 


but i have one eror about not define name.
i make that without name and value function..

When i try with function i don't have idea it will work..

[Youssef221]

This needs an explanation for Yini, I recommend you to read this tutorial: https://sampforum.blast.hk/showthread.php?tid=352703

[kyriakos587]

Use INI_Int("Password", password2);

without '==' i think you will not get any error

[[DOG]irinel1996]

Quote:

Originally Posted by kyriakos587 Use INI_Int("Password", password2); without '==' i think you will not get any error

Wrong.

Since the password is a string you must use INI_String.

https://sampforum.blast.hk/showthread.php?tid=570957

Anyway, I don't know what num_hash is. If it returns an integer, then yes, you're right.

[Pottus]

If I had to do this I certainly wouldn't use y_ini you really are better off biting the bullet and using either sqlite or mysql.

[kyriakos587]

@irinel Lel i just say maybe because i dont know how to use y_ini

[Yashas]

Wait Wait!!

Check this before you start converting your script from dini to y_ini!!!

https://sampforum.blast.hk/showthread.php?tid=574754