[Jose_grana]

In my gm I save the date in a string with the format Day / Month / Year.

Example:

02/21/1990

How could I get the age by getting the current server date?

Example.

21/02/1990.- 12/08/2018 = 28 years.

+1 reputation

[Jefff]

pawn Код:

new Age = strval(date_now[6]) - strval(birth_date[6]);

[Gammix]

PHP код:

numdays(year, month) {
    switch (month) {
        case 4, 6, 9, 11: {
            return 30;
          }
        case 2: {
            if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)) {
                return 29;
            }
            return 28;
          }
    }
    
    return 31;
}
getage(birth_year, birth_month, birth_day) {
    new current_year, current_month, current_day;
    getdate(current_year, current_month, current_day);
    new sum;
    new cumulative_days[12];
    for (new i = 0; i < 12; ++i){
        sum += numdays(current_year, i);
        cumulative_days[i] = sum;
    }
    
    new age = (current_year - birth_year - 1);
    
    new days_this_year = (current_day + cumulative_days[current_month - 1]);
    new days_birth_year = (cumulative_days[11] - (birth_day + cumulative_days[birth_month - 1]));
    
    new total_days = (days_this_year + days_birth_year);
    
    age += total_days/365;
       return age;
}
// how to use
printf("Age: %i", getage(1995, 6, 30)); 


[Jefff]

Why not

pawn Код:

new Age = current_year - birth_year;

? xd

[Private200]

Quote:

Originally Posted by Jefff Why not pawn Код: new Age = current_year - birth_year; ? xd

cause it will be inaccurate once it comes to specific days (everyone from 1998 would be the same age in 201.

[CaptainBoi]

you can do it by taking the birth year and taking todays year
and make a format in which its going to take subtracted
then send client message
this is your age

[Jose_grana]

Quote:

Originally Posted by Gammix PHP код: numdays(year, month) {     switch (month) {         case 4, 6, 9, 11: {             return 30;           }         case 2: {             if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)) {                 return 29;             }             return 28;           }     }          return 31; } getage(birth_year, birth_month, birth_day) {     new current_year, current_month, current_day;     getdate(current_year, current_month, current_day);     new sum;     new cumulative_days[12];     for (new i = 0; i < 12; ++i){         sum += numdays(current_year, i);         cumulative_days[i] = sum;     }          new age = (current_year - birth_year - 1);          new days_this_year = (current_day + cumulative_days[current_month - 1]);     new days_birth_year = (cumulative_days[11] - (birth_day + cumulative_days[birth_month - 1]));          new total_days = (days_this_year + days_birth_year);          age += total_days/365;        return age; } // how to use printf("Age: %i", getage(1995, 6, 30));

Your code works perfect but only when defining the day, month and year.

My code:

pawn Код:

enum pInfo
{
    pBirthDate[24]
};
new PlayerInfo[MAX_PLAYERS][pInfo];

//Load variable

pawn Код:

cache_get_value_name(0, "Birthdate", PlayerInfo[extraid][pBirthDate],24);

//To modify the variable

pawn Код:

format(PlayerInfo[playerid][pBirthDate], 24, inputtext);

How can I use your function like this?

Thanks for you time!.

[Gammix]

You'll have to split your string.
If your birthdate has this type of format: "21/02/1990"

You can do something like this:

PHP код:

test_function() {
    new string[] = "21/02/1990";

    new year, month, day;
    new pos, tmp[5];

    strmid(tmp, string, 0, (pos = strfind(string, "/", true, 0)));
    day = strval(tmp);
    
    strmid(tmp, string, pos + 1, (pos = strfind(string, "/", true, pos + 1)));
    month = strval(tmp);
    
    strmid(tmp, string, pos + 1, strlen(string));
    year = strval(tmp);

    printf("%i/%i/%i", day, month, year);
}