[NeXoR]

So, I have been told to find the smallest number in an array, that's what I did

PHP код:

    // Task 1
    new biggest = 0;
    for(new i = 0; i < sizeof(Arr); i++) if(Arr[i] > biggest) biggest = Arr[i];
    printf("The highest number is: %d", biggest);
    // Task 2
    new smallest = biggest;
    for(new i = 0; i < sizeof(Arr); i++) if(Arr[i] < smallest) smallest = Arr[i];
    printf("The smallest number is: %d", smallest); 


And my fellow scripter told me that there is another way to do it, instead of run two loops I can run only one
And he gave me a hint to use hexa numbers, anyone's got a clue ?

[Vince]

Not sure why you would need hexadecimal numbers, except perhaps to represent the highest and lowest possible numbers. After a while you know those by heart: 0x7FFFFFFF is the largest possible number that can be stored in a 32-bit unsigned integer. This is equal to roughly 2.14 billion. Likewise, 0x80000000 is the smallest possible number, equal to -2.14 billion.

And yes, if you need to find both lowest and highest then you can indeed bundle them in a single loop.

[SickAttack]

pawn Код:

new array[] = {3, 7, 2, 4, 5, 8, 2, 9, 2, 1, 3, 5, 6, 7}, highest, lowest = 9999;
for(new i = 0; i < sizeof(array); i ++)
{
    if(array[i] > highest)
    {
        highest = array[i];
    }
    else if(array[i] < lowest)
    {
        lowest = array[i];
    }
}

printf("Highest: %d", highest);
printf("Lowest: %d", lowest);

[NeXoR]

Quote:

Originally Posted by SickAttack pawn Код: new array[] = {3, 7, 2, 4, 5, 8, 2, 9, 2, 1, 3, 5, 6, 7}, highest, lowest = 9999; for(new i = 0; i < sizeof(array); i ++) {     if(array[i] > highest)     {         highest = array[i];     }     else if(array[i] < lowest)     {         lowest = array[i];     } } printf("Highest: %d", highest); printf("Lowest: %d", lowest);

That's the point, I have been asked to get the lowest number, without stating a number beforehand (without lowest = 9999) so it can get the lowest number no matter what the highest is.
Do you know a way to do it ?
I mean doing the Task 2 point without using task1 or stated variables (lowest = X)

[SickAttack]

Quote:

Originally Posted by NeXoR That's the point, I have been asked to get the lowest number, without stating a number beforehand (without lowest = 9999) so it can get the lowest number no matter what the highest is. Do you know a way to do it ? I mean doing the Task 2 point without using task1 or stated variables (lowest = X)

pawn Код:

new array[] = {3, 7, 2, 4, 5, 8, 2, 9, 2, 1, 3, 5, 6, 7}, lowest = array[0];
for(new i = 1; i < sizeof(array); i ++)
{
    if(array[i] < lowest)
    {
        lowest = array[i];
    }
}

printf("Lowest: %d", lowest);

You have to initialize the variable, because it starts at 0. Now it should work regardless of what the highest number is.

[NeXoR]

Quote:

Originally Posted by SickAttack pawn Код: new array[] = {3, 7, 2, 4, 5, 8, 2, 9, 2, 1, 3, 5, 6, 7}, lowest = array[0]; for(new i = 1; i < sizeof(array); i ++) {     if(array[i] < lowest)     {         lowest = array[i];     } } printf("Lowest: %d", lowest); You have to initialize the variable, because it starts at 0. Now it should work regardless of what the highest number is.

That should make it, I would have repped you if I could I just did it too soon xD

[Jayse]

I know you fixed it already, but I would like to share this for anyone who's looking for a function like this (not expecting anything)

PHP код:

returnLowestValue( arr[ ], len ) {
    new val = 0x7FFFFFFF;
    for( new i; i < len; i ++ ) if( arr[ i ] < val ) val = arr[ i ];
    return val;
} 


[SickAttack]

Quote:

Originally Posted by Jayse I know you fixed it already, but I would like to share this for anyone who's looking for a function like this (not expecting anything) PHP код: returnLowestValue( arr[ ], len ) {     new val = 0x7FFFFFFF;     for( new i; i < len; i ++ ) if( arr[ i ] < val ) val = arr[ i ];     return val; }

That's what Vince explained. I guess it's better to just assign the first value of the array to the variable since it will cut one cycle off the loop.

[NeXoR]

Quote:

Originally Posted by Jayse I know you fixed it already, but I would like to share this for anyone who's looking for a function like this (not expecting anything) PHP код: returnLowestValue( arr[ ], len ) {     new val = 0x7FFFFFFF;     for( new i; i < len; i ++ ) if( arr[ i ] < val ) val = arr[ i ];     return val; }

I'll take a note of it, thanks.