18.08.2015, 07:29
COMMAND:topxp(playerid, params[])
its just showing 1 player..
Код:
{
new p_top[24],score,string[600],row[600];
mysql_query("SELECT playerName, playerXP FROM playerdata ORDER BY playerXP DESC Limit 10");
mysql_store_result();
mysql_fetch_row(row);
sscanf(row, "p<|>s[600]d",p_top,score);
format(string, sizeof string, "Top Player: %s | XP: %d",p_top,score);
mysql_free_result();
ShowPlayerDialog(playerid, 108, DIALOG_STYLE_MSGBOX,"Top Player", string, "Close", "");
return 1;
}


