Help with difficult Math problem
#10

I'm VERY rusty at math so i can't solve it (mistakes), but since you have

j/11 = x+5 (x is a result of division, we don't care about it)

you must transform the equation so it'll look like this:

(3j + 2)/11 = kx+l

where l is the remainder

EDIT:
I did it, answer is 6 but i had to modify it xD

Quote:

j/11 = x+5 | *3
3j/11 = 3x+15 | +2
(3j+2)/11 = 3x+17 BUT since 17 is divisible by 11 with remainder:
(3j+2)/11 = 4x+6
I'm not taking any responsibility for this, but since Eng. Drebin says it's 6, it kinda looks good :P
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Messages In This Thread
Help with difficult Math problem - by lolumadd_ - 06.03.2014, 21:43
Re: Help with difficult Math problem - by Kyle - 06.03.2014, 21:46
Re: Help with difficult Math problem - by lolumadd_ - 06.03.2014, 21:54
Re: Help with difficult Math problem - by Kyle - 06.03.2014, 21:57
Re: Help with difficult Math problem - by Hiddos - 06.03.2014, 22:06
Re: Help with difficult Math problem - by lolumadd_ - 06.03.2014, 22:11
Re: Help with difficult Math problem - by Kyle - 06.03.2014, 22:11
AW: Re: Help with difficult Math problem - by Drebin - 06.03.2014, 22:19
Re: Help with difficult Math problem - by lolumadd_ - 06.03.2014, 22:21
Re: Help with difficult Math problem - by DiDok - 06.03.2014, 22:21

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