Help with difficult Math problem -
lolumadd_ - 06.03.2014
Question:
If
j is a positive integer and the remainder when
j is divided by 11 is 5, what is the remainder when 3j + 2 is divided by 11?
___________
So, its obvious that I need to find the dividend (right?) to use to find 3j + 2 / 11. But how can I find that If I don't even have the quotient?
I know the equation
dividend = divisor * quotient + remainder
But with the few terms given it would come out to
x = 11y + 5 which is far as I'm aware - impossible to solve.
Thanks for any help.
Re: Help with difficult Math problem -
Kyle - 06.03.2014
I'm not sure about this but this looks like the ecologic moduli problem.
I will get some people to come and have a look for you.
If nothing helpful replies, try:
http://www.fiverr.com/edu_coach/answ...-math-question
EDIT: Sorry I sound drunk today.
Re: Help with difficult Math problem -
lolumadd_ - 06.03.2014
Quote:
Originally Posted by KyleSmith
|
Holy shit $5 for just one question, is he reinventing the pythagorean theorem or something lol?
Re: Help with difficult Math problem -
Kyle - 06.03.2014
Quote:
Originally Posted by lolumadd_
Holy shit $5 for just one question, is he reinventing the pythagorean theorem or something lol?
|
It's useful, but probably useful if you have a super complex question. Private tutors cost like 41$ an hour if they're qualified, so $5 isn't too bad xD.
Re: Help with difficult Math problem -
Hiddos - 06.03.2014
3(j + 2)/11 = 5
11(3j + 2)/11 = 55
33j + 22 = 55
33j = 33
j = 1
difficult ?ї? ?
Re: Help with difficult Math problem -
lolumadd_ - 06.03.2014
Not right. 5 is the remainder not the quotient. Sorry, Hiddos, it's not that easy
Re: Help with difficult Math problem -
Kyle - 06.03.2014
Quote:
Originally Posted by Hiddos
3(j + 2)/11 = 5
11(3j + 2)/11 = 55
33j + 22 = 55
33j = 33
j = 1
difficult ?ї? ?
|
* Kyle sends 5 usd to hiddos.
EDIT: Maybe not. He has now left the IRC (I referred him). Maybe he will see your reply.
AW: Re: Help with difficult Math problem -
Drebin - 06.03.2014
Quote:
Originally Posted by Hiddos
3(j + 2)/11 = 5
11(3j + 2)/11 = 55
33j + 22 = 55
33j = 33
j = 1
difficult ?ї? ?
|
So when j = 1 then the remainder of j/11 is 5
n0pe
6, sit down.
Re: Help with difficult Math problem -
lolumadd_ - 06.03.2014
Oh my god that works (6). How the fuck did you get that. Please explain.
Re: Help with difficult Math problem -
DiDok - 06.03.2014
I'm VERY rusty at math so i can't solve it (mistakes), but since you have
j/11 = x+5 (x is a result of division, we don't care about it)
you must transform the equation so it'll look like this:
(3j + 2)/11 =
kx+
l
where
l is the remainder
EDIT:
I did it, answer is 6 but i had to modify it xD
Quote:
j/11 = x+5 | *3
3j/11 = 3x+15 | +2
(3j+2)/11 = 3x+17 BUT since 17 is divisible by 11 with remainder:
(3j+2)/11 = 4x+6
|
I'm not taking any responsibility for this, but since Eng. Drebin says it's 6, it kinda looks good :P