[[DOG]irinel1996]

e means that the variables where will be the data asigned are from an enum, nothing else. And the p is the same with or without e.
If you do that:

pawn Код:

enum Vars
{
    name[24], //string = s[24].
    age //integer = i
};
new example[MAX_PLAYERS][Vars];
//---------------------
sscanf(query,"e<p<|>s[24]i>",example[playerid][name],example[playerid][age]);

Hope you understand..