[Ajuda] error 001: expected token: "-string end-", but found "-identifier-"
#1

Jб revisei o cуdigo um milhгo de vezes e nгo encontrei o erro.
Код:
    {
        ShowPlayerDialog(playerid, DIALOG_LOGAR, DIALOG_STYLE_INPUT,""BRANCO"Logar",""BRANCO"Digite sua senha abaixo para logar.","Logar","Sair");
	}
Код:
C:\Users\Robson\Desktop\CRIANDO\filterscripts\Login.pwn(30) : error 001: expected token: "-string end-", but found "-identifier-"
C:\Users\Robson\Desktop\CRIANDO\filterscripts\Login.pwn(30) : warning 215: expression has no effect
C:\Users\Robson\Desktop\CRIANDO\filterscripts\Login.pwn(30) : error 001: expected token: ";", but found "-string-"
C:\Users\Robson\Desktop\CRIANDO\filterscripts\Login.pwn(30) : warning 215: expression has no effect
C:\Users\Robson\Desktop\CRIANDO\filterscripts\Login.pwn(30) : error 001: expected token: "-string end-", but found "-identifier-"
C:\Users\Robson\Desktop\CRIANDO\filterscripts\Login.pwn(30) : fatal error 107: too many error messages on one line

Compilation aborted.Pawn compiler 3.2.3664	 	 	Copyright © 1997-2006, ITB CompuPhase


4 Errors.
Reply
#2

PHP код:
#define HEX_BRANCO     "{FFFFFF}"
ShowPlayerDialog(playeridDIALOG_LOGARDIALOG_STYLE_INPUT,""HEX_BRANCO"Logar",""HEX_BRANCO"Digite sua senha abaixo para logar.","Logar","Sair"); 
Reply
#3

Mesmo erro
Reply
#4

PHP код:
ShowPlayerDialog(playeridDIALOG_LOGARDIALOG_STYLE_INPUT,"{FFFFFF}Logar","{FFFFFF}Digite sua senha abaixo para logar.","Logar","Sair"); 
Reply


Forum Jump:


Users browsing this thread: 1 Guest(s)