[Ajuda] error 001: expected token: "-string end-", but found "-identifier-" - Printable Version
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+---- Thread: [Ajuda] error 001: expected token: "-string end-", but found "-identifier-" (
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error 001: expected token: "-string end-", but found "-identifier-" -
Sloww - 27.02.2017
Jб revisei o cуdigo um milhгo de vezes e nгo encontrei o erro.
Код:
{
ShowPlayerDialog(playerid, DIALOG_LOGAR, DIALOG_STYLE_INPUT,""BRANCO"Logar",""BRANCO"Digite sua senha abaixo para logar.","Logar","Sair");
}
Код:
C:\Users\Robson\Desktop\CRIANDO\filterscripts\Login.pwn(30) : error 001: expected token: "-string end-", but found "-identifier-"
C:\Users\Robson\Desktop\CRIANDO\filterscripts\Login.pwn(30) : warning 215: expression has no effect
C:\Users\Robson\Desktop\CRIANDO\filterscripts\Login.pwn(30) : error 001: expected token: ";", but found "-string-"
C:\Users\Robson\Desktop\CRIANDO\filterscripts\Login.pwn(30) : warning 215: expression has no effect
C:\Users\Robson\Desktop\CRIANDO\filterscripts\Login.pwn(30) : error 001: expected token: "-string end-", but found "-identifier-"
C:\Users\Robson\Desktop\CRIANDO\filterscripts\Login.pwn(30) : fatal error 107: too many error messages on one line
Compilation aborted.Pawn compiler 3.2.3664 Copyright © 1997-2006, ITB CompuPhase
4 Errors.
Respuesta: error 001: expected token: "-string end-", but found "-identifier-" -
SammyJ - 27.02.2017
PHP код:
#define HEX_BRANCO "{FFFFFF}"
ShowPlayerDialog(playerid, DIALOG_LOGAR, DIALOG_STYLE_INPUT,""HEX_BRANCO"Logar",""HEX_BRANCO"Digite sua senha abaixo para logar.","Logar","Sair");
Re: error 001: expected token: "-string end-", but found "-identifier-" -
Sloww - 01.03.2017
Mesmo erro
Re: error 001: expected token: "-string end-", but found "-identifier-" -
IlanZ - 01.03.2017
PHP код:
ShowPlayerDialog(playerid, DIALOG_LOGAR, DIALOG_STYLE_INPUT,"{FFFFFF}Logar","{FFFFFF}Digite sua senha abaixo para logar.","Logar","Sair");