[BuLLeT[LTU]]

Hello. How to make this work good? I was trying many things but it don't work

Код:

stock PlayerIsConnected(playerid)
{
if(IsPlayerConnected(playerid) && playerDB[playerid][Authed] == 1 && !IsPlayerNPC(playerid))
return playerid;
}

[ikey07]

dont use stock, use forward and public, or there cant be this combination

[BuLLeT[LTU]]

warning 209: function "PlayerIsConnected" should return a value

[legodude]

should'nt it return yes or no?(true false)

if so its:

Код:

stock PlayerIsConnected(playerid)
{
if(IsPlayerConnected(playerid) && playerDB[playerid][Authed] == 1 && !IsPlayerNPC(playerid))
{
return 1;
}
return 0;
}

[WackoX]

Quote:

Originally Posted by ikey07 dont use stock, use forward and public, or there cant be this combination

Yes there can be, just use nothing and it works fine.

[Vince]

pawn Код:

#define IsPlayerConnected(%0) \
    (IsPlayerConnected(%0) && playerDB[%0][Authed] == 1 && !IsPlayerNPC(%0))

Now use IsPlayerConnected as you normally would, and it should work.

[BuLLeT[LTU]]

Quote:

Originally Posted by legodude should'nt it return yes or no?(true false) if so its: Код: stock PlayerIsConnected(playerid) { if(IsPlayerConnected(playerid) && playerDB[playerid][Authed] == 1 && !IsPlayerNPC(playerid)) { return 1; } return 0; }

Thank you