PlayerIsConnected function help

PlayerIsConnected function help - Printable Version

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+---- Thread: PlayerIsConnected function help (/showthread.php?tid=165301)

PlayerIsConnected function help - BuLLeT[LTU] - 04.08.2010

Hello. How to make this work good? I was trying many things but it don't work

Код:

stock PlayerIsConnected(playerid)
{
if(IsPlayerConnected(playerid) && playerDB[playerid][Authed] == 1 && !IsPlayerNPC(playerid))
return playerid;
}

Re: PlayerIsConnected function help - ikey07 - 04.08.2010

dont use stock, use forward and public, or there cant be this combination

Re: PlayerIsConnected function help - BuLLeT[LTU] - 04.08.2010

warning 209: function "PlayerIsConnected" should return a value

Re: PlayerIsConnected function help - legodude - 04.08.2010

should'nt it return yes or no?(true false)

if so its:

Код:

stock PlayerIsConnected(playerid)
{
if(IsPlayerConnected(playerid) && playerDB[playerid][Authed] == 1 && !IsPlayerNPC(playerid))
{
return 1;
}
return 0;
}

Re: PlayerIsConnected function help - WackoX - 04.08.2010

Quote:

Originally Posted by ikey07

dont use stock, use forward and public, or there cant be this combination

Yes there can be, just use nothing and it works fine.

Re: PlayerIsConnected function help - Vince - 04.08.2010

pawn Код:

#define IsPlayerConnected(%0) \
    (IsPlayerConnected(%0) && playerDB[%0][Authed] == 1 && !IsPlayerNPC(%0))

Now use IsPlayerConnected as you normally would, and it should work.

Re: PlayerIsConnected function help - BuLLeT[LTU] - 04.08.2010

Quote:

Originally Posted by legodude

should'nt it return yes or no?(true false)

if so its:

Код:

stock PlayerIsConnected(playerid)
{
if(IsPlayerConnected(playerid) && playerDB[playerid][Authed] == 1 && !IsPlayerNPC(playerid))
{
return 1;
}
return 0;
}

Thank you