Problem ( 1 Error ) a compling..
#1

Код:
C:\Users\Martin\Desktop\cf samp\new\larp.pwn(43813) : error 021: symbol already defined: "NameTimer"
Pawn compiler 3.2.3664	 	 	Copyright © 1997-2006, ITB CompuPhase


1 Error.
Help ?

Theres NewTimer code:
Код:
public NameTimer()
{
	for(new i = 0;i < MAX_PLAYERS;i++)
 	{
	 	if(IsPlayerConnected(i))
 		{
 			for(new q = 0;q < MAX_PLAYERS;q++)
 			{
				if(IsPlayerConnected(q))
				{
 					new Float:p1x;
					new Float:p1y;
					new Float:p1z;
					new Float:p2x;
					new Float:p2y;
					new Float:p2z;
					if(IsPlayerConnected(i) && IsPlayerConnected(q))
					{
						GetPlayerPos(i,p1x,p1y,p1z);
  					GetPlayerPos(q,p2x,p2y,p2z);
						if(GetPointDistanceToPointExMorph(p1x,p1y,p1z,p2x,p2y,p2z) < pdistance)
						{
							if(PlayerInfo[q][pMaskuse] != 1)
	  					{
								ShowPlayerNameTagForPlayer(i,q,1);
							}
	  				}
						else
						{
							ShowPlayerNameTagForPlayer(i,q,0);
						}
          }
        }
      }
    }
	}
}
Source is LARP / Los Angeles RP
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#2

What's so hard to understand from 'symbol already defined: "NameTimer"'

The error tell you everything.
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#3

I dont know how do fix that. im so much begginer scripter
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#4

'NameTimer' is existing in your mode more than one time
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#5

it means you've already told the system what to do when the function is called.... you have two public NameTimer()


like


public NameTimer()
{
blahblahblah
}

public NameTimer()
{
blahblahblahblahblah
}


remove one of them and its fixed
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#6

pawn Код:
public CustomPickups()
{
    new Float:oldposx, Float:oldposy, Float:oldposz;
    new string[128];
    NameTimer();
    for(new i = 0; i < MAX_PLAYERS; i++)
    {
        if(IsPlayerConnected(i))
        {
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#7

Quote:
Originally Posted by hazdog
it means you've already told the system what to do when the function is called.... you have two public NameTimer()


like


public NameTimer()
{
blahblahblah
}

public NameTimer()
{
blahblahblahblahblah
}


remove one of them and its fixed
It's not a one more public for sure, it can be many things.
Reply
#8

Quote:
Originally Posted by hazdog
it means you've already told the system what to do when the function is called.... you have two public NameTimer()


like


public NameTimer()
{
blahblahblah
}

public NameTimer()
{
blahblahblahblahblah
}


remove one of them and its fixed
I have found only one NameTimer
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#9

Help please. Thanks.
Reply
#10

click on the binoculars and search NameTimer
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