[lolumadd_]

Question:

If j is a positive integer and the remainder when j is divided by 11 is 5, what is the remainder when 3j + 2 is divided by 11?

___________

So, its obvious that I need to find the dividend (right?) to use to find 3j + 2 / 11. But how can I find that If I don't even have the quotient?

I know the equation dividend = divisor * quotient + remainder
But with the few terms given it would come out to x = 11y + 5 which is far as I'm aware - impossible to solve.

Thanks for any help.

[Kyle]

I'm not sure about this but this looks like the ecologic moduli problem.

I will get some people to come and have a look for you.

If nothing helpful replies, try: http://www.fiverr.com/edu_coach/answ...-math-question

EDIT: Sorry I sound drunk today.

[lolumadd_]

Quote:

Originally Posted by KyleSmith I'm not sure about this but this looks like the ecologic moduli problem. I will get some people to come and have a look for you. If nothing helpful replies, try: http://www.fiverr.com/edu_coach/answ...-math-question EDIT: Sorry I sound drunk today.

Holy shit $5 for just one question, is he reinventing the pythagorean theorem or something lol?

[Kyle]

Quote:

Originally Posted by lolumadd_ Holy shit $5 for just one question, is he reinventing the pythagorean theorem or something lol?

It's useful, but probably useful if you have a super complex question. Private tutors cost like 41$ an hour if they're qualified, so $5 isn't too bad xD.

[Hiddos]

3(j + 2)/11 = 5
11(3j + 2)/11 = 55
33j + 22 = 55
33j = 33
j = 1

difficult ?ї? ?

[lolumadd_]

Not right. 5 is the remainder not the quotient. Sorry, Hiddos, it's not that easy

[Kyle]

Quote:

Originally Posted by Hiddos 3(j + 2)/11 = 5 11(3j + 2)/11 = 55 33j + 22 = 55 33j = 33 j = 1 difficult ?ї? ?

* Kyle sends 5 usd to hiddos.

EDIT: Maybe not. He has now left the IRC (I referred him). Maybe he will see your reply.

[Drebin]

Quote:

Originally Posted by Hiddos 3(j + 2)/11 = 5 11(3j + 2)/11 = 55 33j + 22 = 55 33j = 33 j = 1 difficult ?ї? ?

So when j = 1 then the remainder of j/11 is 5
n0pe

6, sit down.

[lolumadd_]

Oh my god that works (6). How the fuck did you get that. Please explain.

[DiDok]

I'm VERY rusty at math so i can't solve it (mistakes), but since you have

j/11 = x+5 (x is a result of division, we don't care about it)

you must transform the equation so it'll look like this:

(3j + 2)/11 = kx+l

where l is the remainder

EDIT:
I did it, answer is 6 but i had to modify it xD

Quote:

j/11 = x+5 | *3 3j/11 = 3x+15 | +2 (3j+2)/11 = 3x+17 BUT since 17 is divisible by 11 with remainder: (3j+2)/11 = 4x+6

I'm not taking any responsibility for this, but since Eng. Drebin says it's 6, it kinda looks good :P