[Riggster]

Right I have been looking at this code

pawn Код:

public OnPlayerDeath(playerid, killerid, reason)
{
    // Declare 3 float variables to store the X, Y and Z coordinates in
    new Float:x, Float:y, Float:z;
 
    // Use GetPlayerPos, passing the 3 float variables we just created
    GetPlayerPos(playerid, x, y, z);
 
    // Create a cash pickup at the player's position
    CreatePickup(1212, 4, x, y, z, GetPlayerVirtualWorld(playerid));
   return 1;
}

I was wondering how would I use this code but put use more than one, because if I did this -

pawn Код:

public OnPlayerDeath(playerid, killerid, reason)
{
    // Declare 3 float variables to store the X, Y and Z coordinates in
    new Float:x, Float:y, Float:z;
 
    // Use GetPlayerPos, passing the 3 float variables we just created
    GetPlayerPos(playerid, x, y, z);
 
    // Create a cash pickup at the player's position
    CreatePickup(1212, 4, x, y, z, GetPlayerVirtualWorld(playerid));
   return 1;
}
public OnPlayerSpawn(playerid, killerid, reason)
{
    // Declare 3 float variables to store the X, Y and Z coordinates in
    new Float:x, Float:y, Float:z;
 
    // Use GetPlayerPos, passing the 3 float variables we just created
    GetPlayerPos(playerid, x, y, z);
 
    // Create a cash pickup at the player's position
    CreatePickup(1212, 4, x, y, z, GetPlayerVirtualWorld(playerid));
   return 1;
}

Would it not overlap with each other. Please leave any help below

[arakuta]

I didn't understand what you've done man, neither your question '-'

[Riggster]

Just wondering if I can use new Float, Float:y, Float:z; and GetPlayerPos(playerid, x, y, z); more than once in a script without a overlap

[MattSlater]

It won't overlap since im pretty sure the players would die at different position's each time :P

[arakuta]

Yup. Because it's a local variable, getting destroyed by the last callback bracket, after the return ^^

You can't do twice if it's a global variable, because it's never get destroyed.