[Chipardeur]

Код:

new Float:number;
number = -0.57;

if(number < 0)
{
    number = -number;
    printf("%d", number);
}

Why i have this 1058139013?

I search to transform -0.57 to 0.57

[aoky]

PHP код:

if(number < 0)
{
    number = -number;
    printf("%f", number);
} 


PHP код:

 %d = integer 


PHP код:

 %f = float 


[Chipardeur]

oh yes i'm stupid looool

[aoky]

Mistakes are made, glad I helped.

[Eoussama]

When calculating float numbers, use
floatadd instead of +
floatsub instead of -
floatmul instead of *
floatdiv insrtead of /

More on Floats

[Misiur]

What? No reason for that. See "float.inc" in your pawno include folder - and look at all functions containing "operator" in name - those are operator overloads

[Paulice]

If you only need it once you can do, for example (removing the need of "number = -number;"):

PHP код:

printf("%f", -number); 


You could also do

PHP код:

number *= -1; 


instead of "number = -number;".

[Storm94]

Why are you trying to reinvent the wheel?

Код:

floatabs(Float: value);