#undef with arguments? Is it possible?
#1

Hello guys!

I have a definition:
pawn Код:
#define PFX:%1(%2)  BNS_%1(%2)
I want to use it in multiple include (in my systems), so i have to #undef it.

But... the problem is i can't undef it.

I tried with:
pawn Код:
#undef PFX:%1(%2)
But it gave me this error:
error 020: invalid symbol name "PFX"

Somebody have experiences with this?

Thanks!
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#2

Seems like #undef PFX would do the trick, you may try it.
PHP код:
#undef PFX 
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