[sdt7]

hello guys

i wrote a code but it has an error

my code :

PHP код:

    if(dialogid == DIALOG_LOGIN)
    {
        if(response)
        {
            format(EnteredPass[playerid], 128, "%s", inputtext);
            if(EnteredPass[playerid] == pPass[playerid])
            {
                new query[256];
                format(query, 256, "SELECT * FROM users WHERE pName='%s'", pName[playerid]);
                mysql_function_query(g_Handle, query, true, GetPlayerInfos, "i", playerid);
            }
            else
            {
                ShowPlayerDialog(playerid, DIALOG_LOGIN, DIALOG_STYLE_INPUT, "Vorud", "{FF0000}Kesi Ghablan Ba In Esm Sabte Nam Karde Ast\n{FF6664}Lotfan Baraye Vorud Password Ra Vared Konid", "Vorud", "Khoruj");
                return 0;
            }
        }
        else
        {
            Kick(playerid);
        }
    } 


error

PHP код:

J:\SampServer_R2\gamemodes\lsgl.pwn(376) : error 076: syntax error in the expression, or invalid function call
J:\SampServer_R2\gamemodes\lsgl.pwn(395) : warning 203: symbol is never used: "fields"
J:\SampServer_R2\gamemodes\lsgl.pwn(395) : warning 203: symbol is never used: "rows"
Pawn compiler 3.2.3664              Copyright (c) 1997-2006, ITB CompuPhase
1 Error. 


Line 376 :

PHP код:

mysql_function_query(g_Handle, query, true, GetPlayerInfos, "i", playerid); 


[JordanZaundd]

Put quotations around the function, like:

PHP код:

mysql_function_query(g_Handle, query, true, "GetPlayerInfos", "i", playerid); 


[sdt7]

tnx Bro <3