[danielpalade]

Hello.
How can I calculate the days between two dates like 20.05.2015 and 12.08.2017?
I've searched everywhere, but I can't manage to find anything. Thanks.

[Luicy.]

2015-2017 = 2
2x365 = 730

5-8 = 3
3x30 = 90

20-12 = 8

730+90+8 = 828

This isn't really correct due to the extra day each 4 years,also the 30days a month.

In Pawn;

PHP код:

stock GetDateBetween(year, month, day, byYear, byMonth, byDay) {
     new realYear = year-byYear*365;
     new monthAmount;
     switch(month) {
         case 1: monthAmount = 31;
         case 2: monthAmount = 28;
         case 3: monthAmount = 31;
         case 4: monthAmount = 30;
         case 5: monthAmount = 31;
         case 6: monthAmount = 30;
         case 7: monthAmount = 31;
         case 8: monthAmount = 31;
         case 9: monthAmount = 30;
         case 10: monthAmount = 31;
         case 11: monthAmount = 30;
         case 12: monthAmount = 31;
     }
     new monthAmount2;
     switch(byMonth) {
         case 1: monthAmount2 = 31;
         case 2: monthAmount2 = 28;
         case 3: monthAmount2 = 31;
         case 4: monthAmount2 = 30;
         case 5: monthAmount2 = 31;
         case 6: monthAmount2 = 30;
         case 7: monthAmount2 = 31;
         case 8: monthAmount2 = 31;
         case 9: monthAmount2 = 30;
         case 10: monthAmount2 = 31;
         case 11: monthAmount2 = 30;
         case 12: monthAmount2 = 31;
     }
     new realMonth = monthAmount+monthAmount2;
     new realDay = day-byDay;
     return realYear+realMonth+realDay;
} 


[Gammix]

Here is the magic code: (it take cares of leap years as well)

pawn Код:

rdn(year, month, day) // Rata Die day
{
    if (month < 3)
    {
        year--;
        month += 12;
    }
    return ((365*year) + (year/4) - (year/100) + (year/400) + (((153*month) - 457)/5) + (day - 306));
}

How to use:

pawn Код:

new num_days = (rdn(2017, 1, 1) - rdn(2016, 1, 1));