10.07.2016, 11:25
Quote:
Leave him be, He's new to PHP it looks like.
If you want more assistance i've added your skype. - Alexander |
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PHP код:
<?php
$conn = new mysqli($server, $username, $password, $dbname);
if ($conn->connect_error)
die("Connection failed: " . $conn->connect_error);
if(isset($_POST["submit"])) {
if(!is_null($_POST["username"])) {
if(!is_null($_POST["password"])) {
$username = $conn->real_escape_string(stripslashes($_POST['username']));
$password = sha1($conn->real_escape_string(stripslashes($_POST['password'])));
$sql = "SELECT Username, Password FROM login WHERE Username= '$username' AND Password= '$password'";
$result = $conn->query($sql);
if($result->num_rows > 0) {
echo "logged in.";
}
}
else
echo "Don't leave the password empty.";
}
else
echo "Don't leave the username empty.";
}
$conn->close();
?>
So that's why we can't help you without the html.