[JaydenJason]

How come this gives a tag mismatch?

If I'm right, strlen returns the length of a string with an integer, how come this won't work?

Код:

GetPlayerName(playerid, testname, sizeof(testname));
if(testname[strlen(testname)] == ('s' || 'S' || 'z' || 'Z'))

[Abagail]

What are you trying to do? Something like this?

pawn Код:

new contain;
    for(new i; i < strlen(testname); i++)
    {
        if(testname[i] == 'S' || testname[i] == 's' || testname[i] == 'z' || testname[i] == 'Z')
        {
            contain = 1, break;
        }
    }

[JaydenJason]

All I need to do is to check if the final character of the player's name ends with S or Z

[Abagail]

pawn Код:

new testname[128];
    if(testname[strlen(testname)] == 'S')
    {
        printf("yes");
    }

Seems to compile fine without any warnings.

[Jefff]

pawn Код:

new c, len = strlen(testname);
c = tolower(testname[len-1]);
if(c == 's' || c ==  'z')

[HitManxPLAYER]

-_- idk how i can help u

[BlackBank]

Jeff kinda already explained why your code will give a error.

Quote:

Originally Posted by Jefff pawn Код: new c, len = strlen(testname); c = tolower(testname[len-1]); if(c == 's' || c ==  'z')

The way you write the if-check is not right, you can't check a variable with multiple characters in this way:

PHP код:

if(testname[strlen(testname)] == ('s' || 'S' || 'z' || 'Z')) 


This is the correct way (not optimized):

PHP код:

if(testname[strlen(testname)] == 's' || testname[strlen(testname)] == 'S' || testname[strlen(testname)] == 'z' || testname[strlen(testname)] == 'Z') 


And the better way/optimized code is as follow, like Jefff kinda already showed as an example:

PHP код:

new character = testname[strlen(testname)];
if(character == 's' || character == 'S' || character == 'z' || character == 'Z')