[AnonScripter]

pawn Код:

if(numrand == 0)
        {
            numrand += 0;
        }

if i don't want number "0" includes the random do i put "+= 0" or "+= 1"

[SilentSoul]

You should do the random number +1 like you did but in other way,

pawn Код:

new rand = random(5)+1; // now if the random was 0 it will be +1 so it would be one and always ignores the zero

Another way to do this

pawn Код:

stock randomEx(min, max)
{    
    //Credits to ******    
    new rand = random(max-min)+min;    
    return rand;
}
new rand = randomEx(1,3)l//from one to three

[Konstantinos]

By doing "+= 1" will add + 1 to the variable (which was 0) so numrand will be 1.

Well, you can use min-max values for randoms if you want:

pawn Код:

stock RandomEx(min, max)
{
    return random(max - min) + min;
}

[AnonScripter]

max = 5. min = 1
5 -1 = 4
4+ 1 = 5

so this is the same of random(5)

[Koala818]

Quote:

Originally Posted by AnonScripter max = 5. min = 1 5 -1 = 4 4+ 1 = 5 so this is the same of random(5)

it's random(min, max);

so min=1 max=5

random(5-1)+1=random(4)+1

so if you'l get 0 it will actually be 1 and if you get 3 it will actually be 4

[AnonScripter]

what if u get 4 ?
4 +1 =5

[Koala818]

random(i) will return a random value from 0 to i-1 so you can't get 4.

https://sampwiki.blast.hk/wiki/Random

[Konstantinos]

The isn't a way to get 4. randon(4) will give a number between 0 and 3. So the result (for min 1 and max 5) will be 1, 2, 3, 4

[AnonScripter]

so explain this please:
RandomEx(1,50);

50 - 1 = 49
random(49);
if it will not choose 49, so it will choose 48
48+1 = 49
so 50 is out ?

[Koala818]

Yes. RandomEx posted upper gets a random number from [min, max-1]