12.08.2013, 11:13
Hi there, this time I'm on this side of thread. So
Of course this doesn't work, but is it possible to assign value from macro into normal substitution without arguments?
pawn Код:
#define Example%0\32;%1! #define ABC %1
#define Foobar Result: ABC
Example CBA!
Foobar //Result: CBA
ABC //CBA