[thimo]

I dont know if i can post this here but:
Okay im trying to get the id from the database and set the link to that ID
this is what i got:

PHP код:

        $sql = "SELECT * FROM Clubs"; 
        $rs_result = mysql_query ($sql,$connection); 
        $id = mysql_fetch_row($sql, $connection);
        $totalIds = $row[0]; 


This is the thing i am using in the table:

PHP код:

        <td><? echo "<a href='Clubs.php?id=".$TotalIds."'>" . $row["Name"] . "</a>"; ?></td>

But im getting this warning:

Код:

Warning: mysql_fetch_row() expects parameter 1 to be resource, string given in /home/ws02775/public_html/Clubs.php on line 57

[IstuntmanI]

Change

PHP код:

$sql = "SELECT * FROM Clubs";
$rs_result = mysql_query ($sql,$connection);
$id = mysql_fetch_row($sql, $connection);
$totalIds = $row[0]; 


with

PHP код:

$rs_result = mysql_query ("SELECT * FROM Clubs",$connection);
$row = mysql_fetch_row($rs_result, $connection);
$totalIds = $row[0]; 


Also, this is not a forum for PHP help.

EDIT: I don't think this will do what you wanted.