03.09.2015, 13:40
Quote:
Today I learned that when you declare a function with a name starting with an at sign '@' character, it is automatically detected as a public function.
If you do this: PHP код:
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Quote:
Today i learned there exist an *then in Pawn, like this:
PHP код:
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Код:
Error: Expected token: "(", but found "-identifier-" on line 14