[UsaBoy91]

Why this operator make addition ?

[UsaBoy91]

e.g.:

pawn Код:

print("%d",2^4); // will result 6

[Correlli]

Quote:

Originally Posted by Angel φ e.g.: pawn Код: print("%d",2^4); // will result 6

That won't result anything (it will display bad parameter count - 2, should be 1) because you're using normal print function which can't format placeholders like %d. Use printf function.

[yom]

RTFM, ^ isn't the power operator.

[UsaBoy91]

ok Orb, but i don't get any error and in c# / c++ operator ^ means operator power ...

[yom]

In Pawn unfortunately it isn't, but there is floatpower().

[UsaBoy91]

yes , i know this , but what about ******'s Encrypt System ? Why he used that operator ?

pawn Код:

public Encrypt(string[])
{
      for(new x=0; x < strlen(string); x++)
      {
            string[x] += (3^x) * (x % 15);
            if(string[x] > (0xff)) // 255
            {
                 string[x] -= 256;
            }
      }
      return 1;
}

[yom]

I don't think ****** wrote this shit.

^ IS an operator in Pawn, but not the power operator:

Quote:

e1 ^ e2 results in the bitwise “exclusive or” of e1 and e2.

[Google63]

XOR operator for short.

Bitwise operators:

XOR = ^
AND = &
OR = |
NOT = ~