07.12.2010, 17:57
If I had this:
It would let me in regardless what ever the vars are.
Try to help, Thanks.
But if it was like this spreadout
The second one would work perfect, Its the first code which fucks up. WHY!
pawn Код:
if(var == 1 && var2 == 4 && var3 == 6)
{
printf("lol");
}
Try to help, Thanks.
But if it was like this spreadout
pawn Код:
if(var == 1)
{
if(var2 == 4)
{
if(var3 == 6)
{
}
}
}