[cengiz6155]

enum e_PLAYER_FLAGS (<<= 1)

What does it mean?

[Rafaly]

PLAYER_IS_LOGGED_IN

[cengiz6155]

Quote:

Originally Posted by Rafaly PLAYER_IS_LOGGED_IN

What

[cengiz6155]

What does operator mean? <<= 1

[NaS]

It's a bit shift.

If you have a binary number, eg 0b0101 it will become 0b1010 (all bits are shifted 1 position to the left).

What it does in this case is shift every entries' value 1 to the left per item in the enumerator.

The first one will be 1 (0b1), the second will be 0b10, the third 0b100, etc.
It lets you make a list of flags without having to manually assign a value to each one, it will build the order automatically.

[cengiz6155]

Quote:

Originally Posted by NaS It's a bit shift. If you have a binary number, eg 0b0101 it will become 0b1010 (all bits are shifted 1 position to the left).

What does it do in enum?

[IllidanS4]

It is a way of specifying how the consequent values in an enum get assigned. These two enums are equivalent:

pawn Код:

enum E (<<= 1)
{
    E1 = 1,
    E2,
    E3,
    E4
}

pawn Код:

enum E
{
    E1 = 1, //0b1
    E2 = 1 << 1, //0b10
    E3 = (1 << 1) << 1, //0b100
    E4 = ((1 << 1) << 1) << 1 //0b1000
}

The parentheses can contain bit shift, addition, and multiplication assignment operations. The default operation is (+= 1).

[cengiz6155]

Quote:

Originally Posted by IllidanS4 It is a way of specifying how the consequent values in an enum get assigned. These two enums are equivalent: pawn Код: enum E (<<= 1) {     E1 = 1,     E2,     E3,     E4 } pawn Код: enum E {     E1 = 1, //0b1     E2 = 1 << 1, //0b10     E3 = (1 << 1) << 1, //0b100     E4 = ((1 << 1) << 1) << 1 //0b1000 } The parentheses can contain bit shift, addition, and multiplication assignment operations. The default operation is (+= 1).

Thxxx

[v1k1nG]

One of the best threads ever!