[Bojaa]

This Script Have prob When I join I Must Not See it Just Other members who are in gang or on the faction see it

PHP код:

                if(PlayerInfo[playerid][pFaction] == PlayerInfo[playerid][pFaction] && PlayerInfo[i][pFaction] != 0)
                {
                    format(string, sizeof(string), "*** %s from your faction has logged in.", GetPlayerNameEx(playerid));
                    SendClientMessageEx(playerid, COLOR_JUNIORADMIN, string);
                }
                if(PlayerInfo[playerid][pGang] == PlayerInfo[playerid][pGang] && PlayerInfo[i][pGang] != 255)
                {
                    format(string, sizeof(string), "*** %s from your gang has logged in.", GetPlayerNameEx(playerid));
                    SendClientMessageEx(playerid, COLOR_JUNIORADMIN, string);
                } 


[coool]

Код:

                if(PlayerInfo[playerid][pFaction] == PlayerInfo[playerid][pFaction] && PlayerInfo[i][pFaction] != 0) 
                {

Faction number or any thing other there no time to explain.

[Bojaa]

Quote:

Originally Posted by coool Код: if(PlayerInfo[playerid][pFaction] == PlayerInfo[playerid][pFaction] && PlayerInfo[i][pFaction] != 0) { Faction number or any thing other there no time to explain.

... I Just Wont See It Just others see

[coool]

You are not in the faction, but the others are? yes I am!!!. Even without being in any faction you get the message of faction joining. That's your problem. It is because this sentence

Код:

if(PlayerInfo[playerid][pFaction] == PlayerInfo[playerid][pFaction]

will evaluate true because you are checking if the same variables are equal. And the code nested in will run. To solve this do

Код:

if(PlayerInfo[playerid][pFaction] == //Here the appropriate number of faction)

[Bojaa]

Quote:

Originally Posted by coool You are not in the faction, but the others are? yes I am!!!. Even without being in any faction you get the message of faction joining. That's your problem. It is because this sentence Код: if(PlayerInfo[playerid][pFaction] == PlayerInfo[playerid][pFaction] will evaluate true because you are checking if the same variables are equal. And the code nested in will run. To solve this do Код: if(PlayerInfo[playerid][pFaction] == //Here the appropriate number of faction)

No Im In A faction And On Gang But i wont see that msg Just other members of faction or gang

[khRamin78]

PHP код:

public OnPlayerConnect(playerid)
{
    new string[128];
    if(PlayerInfo[playerid][pFaction] != 0)
    {
        format(string, sizeof(string), "*** %s from your faction has logged in.", GetPlayerNameEx(playerid));
        for(new i;i<MAX_PLAYER;i++)
        {
                    if(i == playerid) continue;
            if(PlayerInfo[playerid][pFaction] == PlayerInfo[i][pFaction])
            {
                SendClientMessage(i,-1,string);
            }
        }
    }
    return 1;
} 


do this method for your gang too it will work for you

[Vin Diesel]

Delete please.

[khRamin78]

PlayerInfo[playerid][pGang] == PlayerInfo[playerid][pGang]

i realy cant understand this part ? why u are using this ? they are always same like using 1=1

[Bojaa]

Quote:

Originally Posted by khRamin78 PlayerInfo[playerid][pGang] == PlayerInfo[playerid][pGang] i realy cant understand this part ? why u are using this ? they are always same like using 1=1

Yes Its False I delted It

[Bojaa]

Quote:

Originally Posted by khRamin78 PHP код: public OnPlayerConnect(playerid) {     new string[128];     if(PlayerInfo[playerid][pFaction] != 0)     {         format(string, sizeof(string), "*** %s from your faction has logged in.", GetPlayerNameEx(playerid));         for(new i;i<MAX_PLAYER;i++)         {                     if(i == playerid) continue;             if(PlayerInfo[playerid][pFaction] == PlayerInfo[i][pFaction])             {                 SendClientMessage(i,-1,string);             }         }     }     return 1; }  do this method for your gang too it will work for you

Im getting this warning
warning 219: local variable "i" shadows a variable at a preceding level