[Karolukas123]

Quote:

Originally Posted by Garwan50 hey, in the beginning of my filterscript i load all animations, just to be sure that they will be played without having to type the command twice. However it crashed the player, is there a safer way to do it ? Or is it just impossible to load every libraries at the same time? thanks!

its easy mate.. just create for example

StartingSomeAnimation(playerid) {
ApplyAnimation(playerid, "CHAINSAW", "CSAW_1", 4.1, 1, 0, 0, 0, 0, 1);

How to use:

in command or else
StartingSomeAnimation(playerid);

[SickAttack]

Quote:

Originally Posted by Garwan50 hey, in the beginning of my filterscript i load all animations, just to be sure that they will be played without having to type the command twice. However it crashed the player, is there a safer way to do it ? Or is it just impossible to load every libraries at the same time? thanks!

Preload the libraries when the player spawns, or wherever you want.

[Garwan50]

hey,

i did that, i tried when the player connect, and then when the player spawn.

Maybe i'll try to load animations with a timer, not everything at once

[Hansrutger]

What is ackslimit for precisely? I've read here, which redirected me here. So I'm guessing it has to do with allowed connections or something, but is there an exact definition somewhere? (Sorry if it's stated somewhere obvious, I have not been able to reach there then...).

[Dayrion]

There is a way to detect the number of time a numeral is repeated in a number?
Example:
3331 : 3 is repeated 3 times and 1, one time.
9955: 9 & 5 2 times

[SickAttack]

Quote:

Originally Posted by Dayrion There is a way to detect the number of time a numeral is repeated in a number? Example: 3331 : 3 is repeated 3 times and 1, one time. 9955: 9 & 5 2 times

Loop, array, done.

[Dayrion]

Quote:

Originally Posted by SickAttack Loop, array, done.

I've already tried.

PHP Code:

Repeat(number)
{
    static
        nb[4],
        done[10],
        a[4] = {1, 1, 1};
    #pragma unused done, nb, a
    nb[0] = number / 1000;
    nb[1] = (number % 1000) / 100;
    nb[2] = (number % 100) / 10;
    nb[3] = number % 10;
    printf("%i & %i & %i & %i", nb[0], nb[1], nb[2], nb[3]);
    for(new i; i < 4; i++)
    {
        printf("\n i: %i", i);
        for(new j; j < 4; j++)
        {
            printf("j: %i » %i & %i", j, nb[i], nb[j]);
            if(nb[i] == nb[j] && i != j)
            {
                printf("Le nombre %i est repete (i: %i & j: %i)", nb[i], i, j);
                done[nb[i]]++;
                // if(a[i] >= 3)
                //     return a[i];
            }
        }
    }
    for(new i; i < 10; i++)
    {
        printf("Le nombre %i est repete %ix", i, done[i]);
    }
    return 1;
} 


[SickAttack]

Quote:

Originally Posted by Dayrion I've already tried.

PHP Code:

// ** INCLUDES
#include <a_samp>
// ** MAIN
main()
{
    print("Loaded \"count_numbers_in_string.amx\".");
    new array[10];
    CountNumbersInString("1672893871653409172564", array);
    for(new i = 0; i < sizeof(array); i ++)
    {
        printf("%d was found %d time(s) in string", i, array[i]);
    }
}
// ** CALLBACKS
public OnGameModeInit()
{
    return 1;
}
public OnGameModeExit()
{
    return 1;
}
// ** FUNCTIONS
stock CountNumbersInString(const string[], array[])
{
    new temp[2];
    for(new i = 0, j = strlen(string); i < j; i ++)
    {
        temp[0] = string[i];
        array[strval(temp)] ++;
    }
    return 1;
} 


[Dayrion]

Thanks...

[RaZVaN ^ xD]

Quote:

Originally Posted by Dayrion PHP Code: //code

That code reminds me of the first year of C programming courses in highschool. I remember this was one of our homeworks.

Let me fix that for you:

Code:

Repeat(number) {
	new count[10];
	
	if(number < 0) 
		number = -number; // this algorithm won't work properly on negative number since array indexes must be positive
	
	while(number) {
		new digit = number%10;
		count[digit]++;
		number /= 10;
	}
	
	for(new i = 0; i < 10; ++i) {
		printf("Digit %d - %d times", i, count[i]);
	}
}

The difference between my code and SickAttack's is that mine takes the number as an integer, while his takes it as a string.

[SickAttack]

Quote:

Originally Posted by RaZVaN ^ xD That code reminds me of the first year of C programming courses in highschool. I remember this was one of our homeworks. Let me fix that for you: Code: Repeat(number) { new count[10]; if(number < 0) number = -number; // this algorithm won't work properly on negative number since array indexes must be positive while(number) { new digit = number%10; count[digit]++; number /= 10; } for(new i = 0; i < 10; ++i) { printf("Digit %d - %d times", i, count[i]); } } The difference between my code and SickAttack's is that mine takes the number as an integer, while his takes it as a string.

You can use valstr to convert an integer to a string.

"new digit" should be out of the loop
the function is just ridiculous

[RaZVaN ^ xD]

Quote:

Originally Posted by SickAttack You can use valstr to convert an integer to a string. "new digit" should be out of the loop the function is just ridiculous

I respected the function header he provided in his post, where number was an integer, not a string. Also, this code is just a snippet I wrote in 2 minutes, based on a simple algorithm, sorry for not having enough time to optimize the hell out of it, even if these micro optimizations have little to no impact in reality.

However, if we're at this subject, then your function is not that bright, too:
- you don't check anywhere if array used to store the counter is large enough
- function would return invalid results for negative numbers
- instead of creating a 2 cell string, copying every character to that string, and then converting it to a number, you could have done something like this instead: "array[(string[i]-'0')] ++;"
- should I bring into discussion the differencies between pre- and post- increments? nah


So, why is my function ridiculous?

[Dayrion]

Quote:

Originally Posted by RaZVaN ^ xD That code reminds me of the first year of C programming courses in highschool. I remember this was one of our homeworks. Let me fix that for you: Code: Repeat(number) { new count[10]; if(number < 0) number = -number; // this algorithm won't work properly on negative number since array indexes must be positive while(number) { new digit = number%10; count[digit]++; number /= 10; } for(new i = 0; i < 10; ++i) { printf("Digit %d - %d times", i, count[i]); } } The difference between my code and SickAttack's is that mine takes the number as an integer, while his takes it as a string.

This is my first year of C programming. ;p
Thanks for your code. It's clear. I don't know why I didnt' tough about this kind of version.
EDIT: I can't +rep because I already did it.

[Logic_]

Is there any possible way to get the first letter of a string only?

PHP Code:

new _test[1];
strcat(_test, pName(playerid));
// or
format(_test, sizeof(_test), "%s", pName(playerid)); 


Found a function called 'Strmid' that may be useful in this @ https://sampwiki.blast.hk/wiki/Strmid but how can i use it?

[Bolex_]

Maybe this ?

https://sampwiki.blast.hk/wiki/Firstchars

[Dignity]

Quote:

Originally Posted by ALiScripter Is there any possible way to get the first letter of a string only? PHP Code: new _test[1]; strcat(_test, pName(playerid)); // or format(_test, sizeof(_test), "%s", pName(playerid));  Found a function called 'Strmid' that may be useful in this @ https://sampwiki.blast.hk/wiki/Strmid but how can i use it?

strmid(dest, source, 0, 1);

[Logic_]

Thanks both of you, but which one will you prefer the most?

[Bolex_]

Quote:

Originally Posted by ALiScripter Thanks both of you, but which one will you prefer the most?

I think a strmid bring in unnecessary lines and usage! I prefer to use Firstchar or do it with strmid on easy way!

[Dayrion]

What that mean ' :: ' ?
I guess : Custom:Variable = 5;
And this ? Custom::Variable = 5;

[Hansrutger]

Check the script defines: "#define Custom::" and you should see an explanation hopefully. If that is actually thing, it's the first time I am seeing that and am sorry for misleading.