[Yaa]

Hello !!

while updating from SQLite to Mysql

i got this warnings in same situations

The line vv

PHP код:

new Result = mysql_query(MySQL, "SELECT * FROM Zones"); 


The errors :

PHP код:

warning 213: tag mismatch 


x 10

Thanks in advence

[oMa37]

new Cache:Results

[Yaa]

Quote:

Originally Posted by oMa37 new Cache:Results

How to do it ??

[Yaa]

nope now it's give me 30 warning from 10

[StrikerZ]

PHP код:

new Result = mysql_query(MySQL, "SELECT * FROM `Zones`"); 


And what are you trying to select from Zones? And you should use this vv always for columns

PHP код:

` ` 


and this vv

PHP код:

' ' 


for values like string,float etc.

[iLearner]

Quote:

Originally Posted by oMa37 new Cache:Results

^^

In mysql you do that, the thing you're doing is for sqlite.