[Type-R]

Hello, well i am making a banking system and i want to make it so, that you have to create an account with a 4-digit pin code. I tried googling and searching around the website, but i could not find what is the best way to detect players input text if it only contains digits?? Thank you.

[PrO.GameR]

Search for isnumeric function..

PS: most of includes do use that, so just give it a try, I'm pretty sure if you are using sscanf it does have that.

[Shinja]

PHP код:

stock isNumeric(string[])
{
    for (new i = 0, j = strlen(string); i < j; i++)
    {
        if (string[i] > '9' || string[i] < '0') return 0;
    }
    return 1;
} 


[Misiur]

If you are using sscanf, then it's just

pawn Код:

if(sscanf(yourstring, "{dddd}")) //fail

Otherwise, something like

pawn Код:

for (new i = 0; i != MAX_PIN_DIGITS; ++i) if(!('0' <= input[i] <= '9')) //fail

//Beaten by fast typers

[Vince]

Quote:

Originally Posted by Misiur If you are using sscanf, then it's just pawn Код: if(sscanf(yourstring, "{dddd}")) //fail

That won't work because those numbers then need to be separated by spaces and in addition can be longer than one character.

[Stinged]

This would work, if you're using sscanf

Код:

if (sscanf(string, "{i}")) // string is not all numbers

[Luicy.]

What about strval?

PHP код:

if(strval(string))) 


[Stinged]

Quote:

Originally Posted by Meller What about strval? PHP код: if(strval(string)))

Wouldn't work. It returns 0 when the string is not a number.
But it also returns 0 when the integer is equal to zero.
That would deny '0000' as a 4 digit pin code.

[NaS]

PHP код:

IsPinCode(input[])
{
    new len = strlen(input);
    if(len != 4) return 0;
    for(new i = 0; i < len; i ++) if(input[i] < '0' || input[i] > '9') return 0;
    return 1;
}