[HBG]

Today I learned that using printf with large strings will crash the server.

[Write]

Today I learned that if you put a plane-swipe command with a public function, it'll delete all of your saved files in the scriptfiles thread therefore you must use swipe commands only.

[jlalt]

Today I learned to make Dialog with string and I made that:

[Tamer]

Quote:

Originally Posted by jlalt Today I learned to make Dialog with string and I made that:

Here's something new for you to learn today, DIALOG_STYLE_TABLIST_HEADERS

https://sampwiki.blast.hk/wiki/Dialog_Styles

https://sampwiki.blast.hk/wiki/Image:Di...st_headers.png

[Inn0cent]

Well, Today i came to know that we can still chat if the gamemode is restarting. Will be good for the servers which have restarting every 5 min. For mission changes.

[Dutheil]

Today I learned that when you declare a function with a name starting with an at sign '@' character, it is automatically detected as a public function.

If you do this:

PHP код:

@test()
{
} 


You will take a "warning 235: public function lacks forward declaration (symbol "@test"), because it is not forward, this means that it is a public function.

[Kaliber]

Today i learned there exist an *then in Pawn, like this:

PHP код:

new a=5;
if a==5 *then print("a=5"); 


Didn't know that

[SecretBoss]

Quote:

Originally Posted by Kaliber Today i learned there exist an *then in Pawn, like this: PHP код: new a=5; if a==5 *then print("a=5");  Didn't know that

Basic C++ or PHP

[Kaliber]

Quote:

Originally Posted by SecretBoss Basic C++ or PHP

Dude...what Pawn has to do with PHP? Right, nothing.

Thats why it wonders me.

[Freezo]

Quote:

Originally Posted by Dutheil Today I learned that when you declare a function with a name starting with an at sign '@' character, it is automatically detected as a public function. If you do this: PHP код: @test() { }  You will take a "warning 235: public function lacks forward declaration (symbol "@test"), because it is not forward, this means that it is a public function.

True, the character '@' declare a public function| @test() -> public test()

Quote:

Originally Posted by Kaliber Today i learned there exist an *then in Pawn, like this: PHP код: new a=5; if a==5 *then print("a=5");  Didn't know that

in samp pawn only, in sourcemod & amxmodx & amxmod, it shows up an error :

Код:

Error: Expected token: "(", but found "-identifier-" on line 14

[Dutheil]

Quote:

Originally Posted by Freezo True, the character '@' declare a public function| @test() -> public test()

Not really, if you put the character '@' before the name, you can't call only the function name.
Example which works :

PHP код:

#include <a_samp>
main()
{
    @test();
}
forward @test();
@test()
{
    print("test");
} 


Example doesn't work :

PHP код:

#include <a_samp>
main()
{
    test();
}
forward test();
@test()
{
    print("test");
} 


Код:

error 004: function "test" is not implemented
warning 235: public function lacks forward declaration (symbol "@test")

[Slice]

@Dutheil: he's talking about public functions (i.e. saved in the public function table in the AMX).

This should work:

pawn Код:

main() {
        CallLocalFunction("@test", "");
}

@test();
@test() {
        printf("test");
}

[Freezo]

Quote:

Originally Posted by Dutheil Not really, if you put the character '@' before the name, you can't call only the function name. Example which works : PHP код: #include <a_samp> main() {     @test(); } forward @test(); @test() {     print("test"); }  Example doesn't work : PHP код: #include <a_samp> main() {     test(); } forward test(); @test() {     print("test"); }  Код: error 004: function "test" is not implemented warning 235: public function lacks forward declaration (symbol "@test")

i dunno what are you trying to say. But yes, i know when you declare it as @test, you will call it as test() and not @test().

@ is like doing public or nothing.

@test() = public test() or test() =

It was just yesterday that i join samp pawn, i was in amxmodx, they don't do forward for such a thing like that.

[Dutheil]

Quote:

Originally Posted by Freezo @test() = public test() or test() =

Check out my examples, you'll see that it's not exactly right.

@Slice : Yes I understood it (not for the forward, but thanks).
What I mean is that if I want to call the function, it will necessarily indicate the at sign '@'

[Freezo]

Quote:

Originally Posted by Dutheil Check out my examples, you'll see that it's not exactly right.

@ -> public = point finale.

Sorry i was meaning that you need to call it with @. But i write the opposite.

[Dutheil]

Quote:

Originally Posted by Freezo @ -> public = point finale. You are doing a call with @ and you expect to the function to be called?

I answered :

Quote:

Originally Posted by Dutheil What I mean is that if I want to call the function, it will necessarily indicate the at sign '@'

[Freezo]

Yes, i was wrong. Because i was thinking to say that you need the '@' but i say the opposite.

[Dutheil]

Aha I don't mind it

[Freezo]

Today i learned that when you declare a stock or a function like :

Код:

stock printf.one() { }

The compiler doesn't manage that, well because of the point '.', and it gives an error of "Undefined symbol", but how can we fix that?

Well its really simple.

1. First, we will need to declare a define
2. the define will basically replace the real one.

Take a look:

Код:

#define printf. _replace_

Код:

stock printf.one() { }
stock printf.two() { }
stock printf.three() { }

What did i do? Well simply i create a define that replace the printf with _replace_ which the compiler will read it like this:

Код:

stock  _replace_one() {}
stock  _replace_two() {}
stock  _replace_three {}

Done.

Edit: i didn't tough that its something made before: Here

[Jpew]

Today i learned the functions for stablish a mysql conection, like this:

Код:

#define SQL_HOST 	("localhost")
#define SQL_USER 	("root")
#define SQL_PASS 	("")
#define SQL_DB		("db")

    mysql_connect(SQL_HOST, SQL_USER, SQL_DB, SQL_PASS);

It's really stupid, but it is something.