[SumX]

Hello!
I want to check if a number is even or uneven.
For those who don't understand: 1 - uneven, 2 - even, 3 - uneven ... etc.

In c++ I am doing this at school by using this:

PHP код:

if(x%2) 


PHP код:

if(x%2 == 0) 


how can I do this in PAWN?

[Abagail]

Do they teach you how to use the search function at school aswell? If not, I think it'd be great if you got that class, because you apparently need it sir.
https://sampforum.blast.hk/showthread.php?tid=70747

[SumX]

I searched only for MOD samp on ******. thank you!

[Alex Magaсa]

I searched on samp wiki and this is the only way i found but the script will look a mess xd:
https://sampwiki.blast.hk/wiki/Control_Structures#else
With ELSE & IF.

[Nero_3D]

Just use that instead of MOD

pawn Код:

#define IsOdd(%0) (%0 & 1)

[Crayder]

Quote:

Originally Posted by Nero_3D Just use that instead of MOD pawn Код: #define IsOdd(%0) (%0 & 1)

This, with this for even:

pawn Код:

#define IsEven(%0) (!IsOdd(%0))

Quote:

Originally Posted by SumX PHP код: if(x%2)  PHP код: if(x%2 == 0)

Those should work too, but binary (thus, the binary AND above) is better.

[Mauzen]

Quote:

Originally Posted by Nero_3D Just use that instead of MOD pawn Код: #define IsOdd(%0) (%0 & 1)

FIY this checks if the last bit is set, so if the binary numbers contains a 1. A clever method, dont think the compiler optimizes this by itself.