Number of arguments doesnt match definition in for
#1

Hello guys, having this error. I dont know how to fix it

pawn Код:
for (new char = fgetchar (file); char != EOF; char = fgetchar (file))
It doesnt show anything, till I use function with this somewhere
Reply
#2

I don't think you can use "char" as a variable name since it's a Pawn keyword.
Reply
#3

Change "char" as its defined within pawno.
Reply
#4

Still same issue.
Reply


Forum Jump:


Users browsing this thread: 2 Guest(s)