[RenovanZ]

Hi, I got this error on my script:

Код:

C:\Users\ariefkyano\Desktop\Test RP\gamemodes\Respect4.pwn(53539) : error 012: invalid function call, not a valid address
C:\Users\ariefkyano\Desktop\Test RP\gamemodes\Respect4.pwn(53539) : warning 215: expression has no effect
C:\Users\ariefkyano\Desktop\Test RP\gamemodes\Respect4.pwn(53539) : error 001: expected token: ";", but found ")"
C:\Users\ariefkyano\Desktop\Test RP\gamemodes\Respect4.pwn(53539) : error 029: invalid expression, assumed zero
C:\Users\ariefkyano\Desktop\Test RP\gamemodes\Respect4.pwn(53539) : fatal error 107: too many error messages on one line

Compilation aborted.Pawn compiler 3.2.3664	 	 	Copyright © 1997-2006, ITB CompuPhase


4 Errors.

and the line is

pawn Код:

if(gPlayerLogged(i) && PlayerInfo[i][BizID] != 0)

I don't know how to fix it, help please

[LarzI]

Ignore this reply - I'm retarded for not seeing the error.

Read to Dwane's reply

[Konstantinos]

Are you using gPlayerLogged as a function or variable?

pawn Код:

// function:
gPlayerLogged(playerid)
{
    // code;
}

// which is..
if(gPlayerLogged(i) && PlayerInfo[i][BizID] != 0)

// --

// variable:
new
    gPlayerLogged[ MAX_PLAYERS ]
;
// which is..
if(gPlayerLogged[i] && PlayerInfo[i][BizID] != 0)

[RenovanZ]

Wrong.

[Konstantinos]

Quote:

Originally Posted by LarzI Show us the line above the error line.

He did on his first post.

Quote:

Originally Posted by Kiyozi_Mu This code that latest i added to my script: pawn Код: foreach(Player, i)         {             if(gPlayerLogged(i) && PlayerInfo[i][BizID] != 0)             {                 PlayerInfo[i][BizID] = 0;                 format(string, sizeof(string), " Administrator %s has sold your business.", playername);                 SendClientMessage(i, COLOR_WHITE, string);             }         }

Read my post and tell me if it is variable, because if it is, you have to use [i] instead of (i).

[RenovanZ]

Quote:

Originally Posted by Dwane Are you using gPlayerLogged as a function or variable? pawn Код: // function: gPlayerLogged(playerid) {     // code; } // which is.. if(gPlayerLogged(i) && PlayerInfo[i][BizID] != 0) // -- // variable: new     gPlayerLogged[ MAX_PLAYERS ] ; // which is.. if(gPlayerLogged[i] && PlayerInfo[i][BizID] != 0)

I use it as variable, then how is the PlayerInfo[i][BizID] != 0) ?

[Konstantinos]

Alright, because it's defined as a variable, you should change it to

pawn Код:

if(gPlayerLogged[i] && PlayerInfo[i][BizID] != 0)

I didn't understand your question about the PlayerInfo[i][BizID] != 0).

[LarzI]

Quote:

Originally Posted by Dwane He did on his first post.

Actually no, he didn't show the line ABOVE the error-line, but it doesn't matter as the error is obviously because he used parentheses instead of square brackets.

[RenovanZ]

Quote:

Originally Posted by Dwane He did on his first post.Read my post and tell me if it is variable, because if it is, you have to use [i] instead of (i).

Thanks! I'm not seeing it

[park4bmx]

If gPlayeralogged is a variable the where is the check ? You cannot use it as a function!

pawn Код:

if(gPlayerLogged[i] == 1&& PlayerInfo[i][BizID] != 0)

If its a stock you can

pawn Код:

stock IsgPlayerLogged(playerid)
{
     if(some_variable) == 1 return 1;
     return 0;
}

Then you check it with the "()" method !