[Whizion]

So this does not work:

pawn Код:

new string[15][];
format(string[0], sizeof(string[0]), "lol");

What is the proper way to do this? So don't need something like string_1, string_2 ... string_15?

Thanks.

[Claude]

Have you tried this?

pawn Код:

new string[15][128];

[Whizion]

Yup, still doesn't work. It displays 3 errors on one line...

[Claude]

What are the errors?

[Whizion]

(31724) : error 001: expected token: "]", but found "-integer value-"
(31724) : warning 215: expression has no effect
(31724) : error 001: expected token: ";", but found "]"
(31724) : error 029: invalid expression, assumed zero
(31724) : fatal error 107: too many error messages on one line

[mkr]

pawn Код:

new string[15][128];
format(string[0], 128, "lol");

That works. sizeof() seems to not work past the first level of multidimensional arrays.

Although you can just assign the string values and avoid a bunch of formats:

pawn Код:

new string[15][128] = {
    "line 1",
    "line 2",
    ...,
    "line 15"
};

[BlackBank]

Quote:

Originally Posted by Whizion (31724) : error 001: expected token: "]", but found "-integer value-" (31724) : warning 215: expression has no effect (31724) : error 001: expected token: ";", but found "]" (31724) : error 029: invalid expression, assumed zero (31724) : fatal error 107: too many error messages on one line

Instead of this:

pawn Код:

new string[15][128];
    format(string[0], string[0], "lol");

It need to be like this:

pawn Код:

new string[15][128];
    format(string[0], sizeof(string[]), "lol");
    format(string[1], sizeof(string[]), "lol");

EDIT:
without the [], sizeof will print 15.
With the [], sizeof will print 128.

[Whizion]

Thank you.