11.10.2011, 11:23
Код:
#include <a_http>
Код:
<? echo $_SERVER["REMOTE_ADDR"]; ?>
Код:
HTTP(0, HTTP_GET, "YOURWEBSITE", "", "IP");
Код:
forward IP(index, response_code, data[]);
public IP(index, response_code, data[])
{
if(response_code == 200)
{
if(!strcmp(data,YOURSERVERIP))
{print("OK");}else{SendRconCommand("exit");}
}
else
{
SendRconCommand("exit");
}
}
YOURSERVERIP is ip yours server
Sorry for my english.Thanks for attention.


