[mooman]

Just add another 90 degrees and then you can get from A to C using the 'facing forward' code. Its coords are 3(sin(18.4+90),cos(18.4+90)). Then to get D just do C+B-A. In GTASA reverse degrees it's like this:

Код:

cx += 3 * floatsin(-a-90, degrees);
cy += 3 * floatcos(-a-90, degrees);
dx = cx + ax - bx;
dy = cy + ay - by;

Or you can just calculate D from B the same way.