command question
#3

i know dini but dont know how to do it like this :
Код:
	if(!dini_Exists(file)) {
		dini_Create(file);
		dini_Set(file,"NOME",Name);
	}
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command question - by iJumbo - 10.05.2010, 15:00
Re: command question - by ViruZZzZ_ChiLLL - 10.05.2010, 15:03
Re: command question - by iJumbo - 10.05.2010, 15:12

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