[Sergei]

@PawnNewCommer,

1. Ah what a fail, you need to format query. You can also use that array 'query' instead of 'result' now, so you don't need to open new 128 cells big one.

Код:

new query[128]; mysql_real_escape_string(password,password);
format(query,sizeof(query),"SELECT * FROM players WHERE id=%d AND password='%s' LIMIT 1",PlayerInfo[playerid][pSQLID],password);
mysql_query(query);
...

2. It should be like this:

Код:

mysql_fetch_field_row(PlayerInfo[playerid][pMarriedTo],"MarriedTo");

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@AlecRae,
I think this would work

Код:

SELECT Name,PhoneNumber FROM players WHERE Name LIKE '%%%s%%'