[M1GU3L]

pawn Код:

mysql_query("CREATE TABLE IF NOT EXIST `cuentas`(
        `id` int(11) NOT NULL autoincrement PRIMARY KEY,
        `nombre` varchar(24) NOT NULL,
        `pass` varchar(50) NOT NULL,
        `nivel` int(1) NOT NULL default `0`)");

Why is this giving me errors? Is there a better way to make it beside using just 1 line?

Errors:

pawn Код:

.pwn(1649) : error 037: invalid string (possibly non-terminated string)
.pwn(1649) : error 017: undefined symbol "TABLE"
.pwn(1649) : error 017: undefined symbol "IF"
.pwn(1649) : fatal error 107: too many error messages on one line