[Spmn]

Quote:

Originally Posted by GRiMMREAPER For x || y, provided both x and y are numbers, will always return 1. You are then accessing arr[1], which indeed exists and is 3. pawn Код: new arr[2] = {1};     if(arr[0 || 1]) {         print("It works!");     } else {         print("It doesn't work."); // Expected output, because arr[0 || 1] returns true (1) and arr[1] doesn't exist.     }

What about arr[0 || 0]?