[xMoBi]

Quote:

Originally Posted by coool TIL This works PHP код: new arr[2] = {1,3}; if(arr[0 || 1])     print("Yea, it works.");  Got the above when lurking my old threads https://sampforum.blast.hk/showthread.php?tid=624112 People are saying that if(arr[1 || 2]) is invalid syntax... But today I checked it works.

What if it's:

Код:

new array[2] = {0, 0};
if (array[0 || 1]) {
    print("Yeah, it works.");
}