19.07.2018, 05:29
TIL
This works
Got the above when lurking my old threads https://sampforum.blast.hk/showthread.php?tid=624112
People are saying that if(arr[1 || 2]) is invalid syntax... But today I checked it works.
This works
PHP код:
new arr[2] = {1,3};
if(arr[0 || 1])
print("Yea, it works.");
People are saying that if(arr[1 || 2]) is invalid syntax... But today I checked it works.