mysql records
#4

PHP код:
new Cache:result mysql_query(DB"SELECT * FROM `Test`");         
         for(new 
icache_num_rows(); != j; ++i)
        {
            
cache_get_value_name(i"Name"Company[Name], 30); 
            
cache_get_value_name(i"Location"Company[Location], 30); 
            
cache_get_value_int(i"Cash"Company[Cash]);
        } 
that should help you.
Reply


Messages In This Thread
mysql records - by Oficer - 11.07.2018, 13:55
Re: mysql records - by Florin48 - 11.07.2018, 13:58
Re: mysql records - by Oficer - 11.07.2018, 14:02
Re: mysql records - by Florin48 - 11.07.2018, 14:10
Re: mysql records - by Oficer - 11.07.2018, 14:21

Forum Jump:


Users browsing this thread: 1 Guest(s)