[GaByM]

Yes, it does return 0 because inside the floatround function you have 3 integers, if you want to do that, you should use this

Quote:

floatround( float(num1)/num2 * 100);

now, num1 becomes a float, so you have at least one floating number in that operation, and it is enough. (when you divide a float with an int or vicevers the result it's a float, in your code you divide 2 integers, and the result is 0 if num1<num2)

BUT!

why not simply do this:

Quote:

new percents = num1*100 / num2;

?