[Kraeror]

Hello guys, I'm using FuNkYTheGreat's method for converting ******* video, but when I enter an ******* video it just appear:

Quote:

Audio stream: http://

Here is the code:

PHP код:

forward Request*******2Mp3( playerid, response_code, data[ ] );
public Request*******2Mp3( playerid, response_code, data[ ] )
{
    if( response_code == 200 )
    {
        new
        start_pos = strfind( data, "\"url\":" ) + 9,
        end_pos = strfind( data, "\"", .pos = start_pos ),
        mp3_coverted_link[700 ];
        strmid( mp3_coverted_link, data,start_pos,end_pos );
        format( mp3_coverted_link, sizeof( mp3_coverted_link ), "http://%s", mp3_coverted_link );
        PlayAudioStreamForPlayer( playerid, mp3_coverted_link );
    }
    else SendClientMessage( playerid, -1, "Couldn't play the song!!!" );
    return 1;
}
stock Play*******Audio( playerid, video_link[ ] )
{
    new
    param_v_idx = strfind( video_link, "?v=" ) + 3,
    video_id[ 500 ],
    payload[ 500 ];
    strmid( video_id, video_link, param_v_idx, strlen( video_link ) );
    format( payload, sizeof( payload ), "www.yt-mp3.com/fetch?v=%s&apikey=1234567", video_id );
    HTTP( playerid, HTTP_GET, payload, "", "Request*******2Mp3" );
    return 1;
} 


And here I'm using it:

PHP код:

for(new i = 0; i <= MAX_PLAYERS; i++)
            {
                if(IsPlayerConnected(i))
                {
                    StopAudioStreamForPlayer(i);
                    Play*******Audio(i, "https://www.youtube.com/watch?v=3QYCqHwlsw4&list=RDMM4NJlUribp3c&index=9");
                }
            }