[Oficer]

Quote:

Originally Posted by IlanZ Sequence of parameters is wrong. Код: sql = mysql_connect("localhost", "user", "db", "123"); Correct: Код: sql = mysql_connect("localhost", "user","123", "db");

Okey thanks
What in this line is wrong?

warning 213: tag mismatch

PHP код:

mysql_format(SqlGM, samp, sizeof(samp), "SELECT * from 'players' WHERE 'nick' LIKE BINARY '%s'", GetPlayerNick(playerid));