sscanf warning: Format specifier does not match parameter count.
#2

Guessing you've got something like this:
Код:
new para1, para2;
sscanf(variable, "ii", para1);
which should be
Код:
new para1, para2;
sscanf(variable, "ii", para1, para2);
It can be writen on soooooo many ways, you gotta look up every sscanf's you've got and fix them.
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