11.04.2017, 07:03
PHP код:
#if !defined isnull
#define isnull(%1) ((!(%1[0])) || (((%1[0]) == '\1') && (!(%1[1]))))
#endif
How to define this ?
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How to define this ? - by NinjaBlack - 11.04.2017, 07:00
Re: How to define this ? - by AbyssMorgan - 11.04.2017, 07:03
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